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105x^2-112x=56x
We move all terms to the left:
105x^2-112x-(56x)=0
We add all the numbers together, and all the variables
105x^2-168x=0
a = 105; b = -168; c = 0;
Δ = b2-4ac
Δ = -1682-4·105·0
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{28224}=168$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-168)-168}{2*105}=\frac{0}{210} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-168)+168}{2*105}=\frac{336}{210} =1+3/5 $
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